Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises: 50

Answer

$\approx 2.695$

Work Step by Step

The base of the logarithm is not $10$, therefore you require the change of base formula before evaluating: $ \log_{25} (5860)$ $= \frac{\log 5860}{\log 25}$ $= 2.69532...$ $\approx 2.695$.
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