## Intermediate Algebra: Connecting Concepts through Application

$f^{-1}(x) = \frac{x-3.6}{0.6}$
$f(x) = 0.6x + 3.6$ Let $f(x) = y$: $y = 0.6x + 3.6$. Switch the variables $x$ and $y$ to find the inverse and solve for $y$: $x = 0.6y + 3.6$ $x - 3.6 = 0.6y$ $y = \frac{x-3.6}{0.6}$ $f^{-1}(x) = \frac{x-3.6}{0.6}$.