Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.1 Functions and Their Inverses - 6.1 Exercises: 37

Answer

$g^{-1}(t) = -\frac{t-8}{4}$

Work Step by Step

$g(t) = -4t + 8$ Let $g(t) = y$: $y = -4t + 8$ Switch the variables $t$ and $y$ to find the inverse: $t = -4y + 8$ $t - 8 = -4y$ $y = -\frac{t-8}{4}$ $g^{-1}(t) = -\frac{t-8}{4}$
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