Answer
$f^{-1}(x) = \frac{x-5}{3}$
Work Step by Step
$f(x) = 3x+ 5$
Let $f(x) = y$:
$y = 3x + 5$
Switch the variables $x$ and $y$ and then solve for $y$:
$x = 3y + 5$
$x - 5 = 3y$
$y = \frac{x-5}{3}$
$f^{-1}(x) = \frac{x-5}{3}.$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.1 Functions and Their Inverses - 6.1 Exercises - Page 494: 35
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