## Intermediate Algebra: Connecting Concepts through Application

$f^{-1}(x) = \frac{x-5}{3}$
$f(x) = 3x+ 5$ Let $f(x) = y$: $y = 3x + 5$ Switch the variables $x$ and $y$ and then solve for $y$: $x = 3y + 5$ $x - 5 = 3y$ $y = \frac{x-5}{3}$ $f^{-1}(x) = \frac{x-5}{3}.$