Answer
No real solution
Work Step by Step
Given$$
\begin{cases}
& y=2 x^2-3 x+7 \\
& y=x-12.
\end{cases}
$$ Set the two equations equal and solve for the values of $x$.
$$
\begin{aligned}
2 x^2-3 x+7 & =x-12 \\
2 x^2-3 x-x & =-7-12 \\
2 x^2-4 x & =-19 \\
x^2-2 x & =-9.5 \\
x^2-2 x+1^2 & =-9.5+1^2 \\
\left(x-4\right)^2 & =-8.5
\end{aligned}
$$ The equation has no real solution.
