Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - Chapter Review Exercises - Page 286: 9



Work Step by Step

($\frac{3a^{-1}b^3c^5}{ab^{-2}c^3}$)$^{-2}$ =($\frac{a^{2}b^{-6}c^{-10}}{9a^{-2}b^{4}c^{-6}}$) =($\frac{a^{(2+2)}}{9b^{(4+6)}c^{(10-6)}}$) =($\frac{a^{4}}{9b^{10}c^{4}}$)
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