#### Answer

45

#### Work Step by Step

(3m$^{-1}$n$^3$p$^{-2}$)$^2$$\times$(5m$^2$n$^{-6}$p$^4$)
=($\frac{3n^3}{mp^2}$)$^2$$\times$($\frac{5m^2p^4}{n^6}$)
=($\frac{9n^6}{m^2p^4}$)$\times$($\frac{5m^2p^4}{n^6}$)
=$\frac{45m^2n^6p^4}{m^2n^6p^4}$=45

Published by
Brooks Cole

ISBN 10:
0-53449-636-9

ISBN 13:
978-0-53449-636-4

45

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