Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - Chapter Review Exercises - Page 286: 1



Work Step by Step

(2x$^3$y$^4$z)$^3$$\times$(5x$^{-3}$y$^2$z)$^{-2}$ =(8x$^9$y$^{12}$z$^3$)$\times$($\frac{1}{25}$x$^6$y$^{-4}$z$^{-2}$) $=\frac{8(x^9)(x^6)(y^{12})(z^3)}{25(y^4)(z^2)}$ $=\frac{8x^{15}y^8z}{25}$
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