Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 2 - Systems of Linear Equations and Inequalities - 2.4 Solving Linear Inequalities - 2.4 Exercises - Page 175: 59

Answer

$d > \frac{6}{7}$

Work Step by Step

Collect constants on the right side of the inequality by subtracting $5$ from each side: $-\frac{7d}{3} < -2$ Multiply each side by $3$ to eliminate the fraction: $-7d < -6$ Divide each side by $-7$ to solve for $d$. Remember that when we divide by a negative number, we need to reverse the sign: $d > \frac{6}{7}$ We check our answer by first substituting our value for $d$ to check for equality: $-\frac{7(\frac{6}{7})}{3} + 5$ ? $3$ Simplify the numerator: $-\frac{6}{3} + 5$ ? $3$ Simplify the fraction: $-2 + 5$ ? $3$ Add or subtract: $3 = 3$ Now that we have proven the equality, we need to substitute a value for $d$ such that $d > \frac{6}{7}$. Let's use $1$ for $d$ to plug into the inequality to see if the inequality still holds true: $-\frac{7(1)}{3} + 5 < 3$ Collect constants on the right side of the inequality: $-\frac{7(1)}{3} < -2$ Simplify the fraction: $-\frac{7}{3} < -2$ Convert the fraction to a decimal: $-2.33 < -2$
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