Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 2 - Systems of Linear Equations and Inequalities - 2.4 Solving Linear Inequalities - 2.4 Exercises - Page 175: 56

Answer

$x \geq -\frac{33}{2}$

Work Step by Step

Collect constants on the right side of the inequality by subtracting $7$ from each side of the inequality: $\frac{4x}{3} \geq -22$ Multiply each side by $3$ to get rid of the fraction: $4x \geq -66$ Divide each side by $4$ to solve for $x$: $x \geq -\frac{66}{4}$ Simplify the fraction by dividing the numerator and denominator by their greatest common factor, $2$: $x \geq -\frac{33}{2}$ Let's check our answer by substituting our value for $x$ into the original inequality to see if our inequality holds true: $7 + \frac{4(-\frac{33}{2})}{3} \geq -15$ Multiply: $7 - \frac{66}{3} \geq -15$ Simplify the fraction: $7 - 22 \geq -15$ Subtract: $-15 \geq -15$ The inequality is true; therefore, our solution is correct.
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