## Intermediate Algebra: Connecting Concepts through Application

Recall: (1) The $x$-intercept of a linear equation can be found by setting $y=0$ then solving for $x$. (2) The $y$-intercept of a linear equation can be found by setting $x=0$ then solving for $y$. Find the $x$-intercept by setting $y=0$ to obtain: \begin{align*} 10x-25y&=100\\ 10x-25(0)&=100\\ 10x&=100\\ x&=\frac{100}{10}\\ x&=10 \end{align*} Thus, the $x$-intercept is $(10, 0)$. Find the $y$-intercept by setting $x=0$ to obtain: \begin{align*} 10x-25y&=100\\ 10(0)-25y&=100\\ -25y&=100\\ y&=\frac{100}{-25}\\ y&=-4 \end{align*} Thus, the $y$-intercept is $(0, -4)$. Plot the intercepts and connect them using a straight line. Refer to the graph above.