Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.4 Intercepts and Graphing - 1.4 Exercises - Page 63: 57

Answer

Refer to the graph below.
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Work Step by Step

Simplify the equation to obtain: \begin{align*} y+2&=2(x)+2(4)-2x\\ y+2&=2x+8-2x\\ y+2&=8\\ y&=8-2\\ y&=6\\ \end{align*} Recall: The graph of an equation of the form $y=k$ is a horizontal line that passes through the point $(0, k)$. All points on the line have a $y$-coordinate of $k$, and the graph has no $x$-intercept unless $k=0$. Thus, the graph of the given line is a horizontal line that passes through $(0, 6)$. The graph has no $x$-intercept. Refer to the graph above.
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