Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.4 Intercepts and Graphing - 1.4 Exercises - Page 63: 27

Answer

$$x_{intercept} = (-\frac{16}{3}, 0)$$ $$y_{intercept} = (0, 8)$$

Work Step by Step

To find the intercepts, one substitutes the opposite variable by zero and solves the equation. To find the $x_{intercept}$, for instance: $$-3x + 2(0) = 16$$ $$-3x = 16$$ $$x = -\frac{16}{3}$$ To find the $y_{intercept}$: $$-3(0) + 2y = 16$$ $$2y = 16$$ $$y = 8$$ Finally, to draw the graph of the equation, one plots the intercepts and draws the line connecting them.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.