Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-9 - Cumulative Review: 95

Answer

$\frac{\sqrt {14ab}}{2b}$

Work Step by Step

Step 1: $\frac{\sqrt {7a}}{\sqrt {2b}}$ Step 2: Rationalize the denominator: $\frac{\sqrt {7a}}{\sqrt {2b}}\times\frac{\sqrt {2b}}{\sqrt {2b}}$. Step 3: $\frac{\sqrt {7a}\times\sqrt {2b}}{\sqrt {2b}\times\sqrt {2b}}$ Step 4: $\frac{\sqrt {7a\times2b}}{2b}$ Step 5: $\frac{\sqrt {7a\times2b}}{2b}$ Step 6: $\frac{\sqrt {14ab}}{2b}$
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