Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-9 - Cumulative Review - Page 764: 100



Work Step by Step

Step 1: $(11-3i)(8+2i)$ Step 2: $11(8+2i)-3i(8+2i)$ Step 3: $88+22i-24i-6i^{2}$ Step 4: $88-2i-6i^{2}$ Step 5: As $i^{2}=-1$, the expression becomes $88-2i-6(-1)=88+6-2i=94-2i$
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