Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-9 - Cumulative Review: 101

Answer

$\frac{5}{4}+ \frac{-3}{2}i$

Work Step by Step

Step 1: $\frac{6+5i}{4i}$ Step 2: $\frac{6+5i}{4i}\frac{i}{i}$ Step 3: $\frac{i(6+5i)}{4i^{2}}$ Step 4: As $i^{2}=-1$, we get $\frac{6i+5(-1)}{4(-1)}$. Step 5: $\frac{6i-5}{-4}$ Step 6: $\frac{6i}{-4}+\frac{(-5)}{(-4)}$ Step 7: $\frac{5}{4}+ \frac{-3}{2}i$
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