Answer
$(z - 2)(z^2 + 2z + 4)$
Work Step by Step
First, we can factor out what is common to the terms:
$5(z^3 - 8)$
The expression in parentheses features the difference of two cubes. The formula for factoring the difference of two cubes is the following:
$a^3 - b^3 = (a - b)(a^2 + ab + b^2)$
In our expression, $a = z$ and $b = 2$.
Let's rewrite our expression in factored form:
$(z - 2)(z^2 + 2z + 4)$
