Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-4 - Cumulative Review: 67

Answer

$\frac{3}{2}$g$^2$h$^4$

Work Step by Step

$\frac{24g^3h^6}{16gh^2}$ $\frac{3g^3h^6}{2gh^2}$ $\frac{3}{2}$g$^{(3-1)}$h$^{(6-2)}$ $\frac{3}{2}$g$^{2}$h$^{4}$
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