Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-4 - Cumulative Review: 65

Answer

$\frac{81}{625}$m$^{16}$n$^{20}$

Work Step by Step

($\frac{3}{5}$m$^4$n$^5$)$^4$ ($\frac{3}{5}$)$^4$m$^{(4\times4)}$n$^{(5\times4)}$ $\frac{3^4}{5^4}$m$^{16}$n$^{20}$ $\frac{3^4}{5^4}$m$^{16}$n$^{20}$ $\frac{81}{625}$m$^{16}$n$^{20}$
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