Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 601: 25

Answer

$\dfrac{\sqrt[4]{xy^3}}{3y^2}$

Work Step by Step

Rationalizing the denominator or $ \dfrac{\sqrt[4]{x}}{\sqrt[4]{81y^5}} $ simplifies to \begin{array}{l} \dfrac{\sqrt[4]{x}}{\sqrt[4]{3^4y^4\cdot y}} \\\\= \dfrac{\sqrt[4]{x}}{3|y|\sqrt[4]{y}} \\\\= \dfrac{\sqrt[4]{x}}{3|y|\sqrt[4]{y}}\cdot\dfrac{\sqrt[4]{y^3}}{\sqrt[4]{y^3}} \\\\= \dfrac{\sqrt[4]{xy^3}}{3|y|\sqrt[4]{y^4}} \\\\= \dfrac{\sqrt[4]{xy^3}}{3|y|\cdot|y|} \\\\= \dfrac{\sqrt[4]{xy^3}}{3y^2} .\end{array}
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