Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 24e



Work Step by Step

$\sqrt[3] (-125y^{6})=\sqrt[3] (-125\times y^{6})=\sqrt[3] (-125)\times\sqrt[3] (y^{6})=-5y^{2}$ We know this because $(-5)^{3}=-125$ and $(y^{2})^{3}=y^{2\times3}=y^{6}$
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