Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 601: 23f

Answer

$x+10\sqrt{x-3}+22$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$, the expression $ \left( \sqrt{x-3}+5 \right)^2 $ simplifies to \begin{array}{l} \left( \sqrt{x-3} \right)^2+2\left( \sqrt{x-3} \right)(5)+(5)^2 \\\\= x-3+10\sqrt{x-3}+25 \\\\= x+10\sqrt{x-3}+22 .\end{array}
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