Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 502: 62

Answer

jogging at 6 mph, biking at 10 mph

Work Step by Step

jogging at $x$ mph for 3 miles, biking at $x+4$ mph for 5 miles total time is 1 hour $3/x + 5/(x+4) = 1$ $x*(x+4)*(3/x + (5/(x+4))) = 1*x*(x+4)$ $3(x+4) + 5*x = x^4+4x$ $3x+12+5x=x^2+4x$ $8x+12 = x^2+4x$ $8x+12-8x-12 = x^2+4x-8x-12$ $0 = x^2-4x-12$ $0=(x-6)(x+2)$ $x-6=0$ $x=6$ $x+2=0$ $x=-2$ (not a valid answer since we can't have a negative speed) $x+4$ $6+4=10$
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