## Intermediate Algebra (6th Edition)

The solution is $12$.
The given equation can be written as: $$(p^2)^2-p^2-20=0$$ Use the Zero Factor Property by equating each factor to zero, then solve each equation to obtain: \begin{array}{ccc} \\&x-12=0 &\text{or} &x-3=0 \\&x=12 &\text{or} &x=3 \end{array} Note that $3$ does not satisfy the original equation so it is not a solution. Therefore, the solution is $12$.