## Intermediate Algebra (6th Edition)

The solutions are $m=2$ and $m=5$.
Let $u=m-6$ Rewrite the given equation using the variable $u$ to obtain: $u^2+5u+4=0$ Factor the trinomial to obtain: $(u+4)(u+1)=0$ Use the Zero-Factor Property by equating each unique factor to zero. then solve: $u+4 = 0 \text{ or } u+1=0 \\u=-4 \text{ or } u=-1$ Since $u=m-6$, then \begin{array}{ccc} &u= -4 &\text{or} &u=-1 \\&m-6=-4 &\text{or} &m-6=-1 \\&m=-4+6 &\text{or} &m=-1+6 \\&m=2 &\text{or} &m=5 \end{array} Thus, the solutions are $m=2$ and $m=5$.