Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.2 - Solving Quadratic Equations by the Quadratic Formula - Exercise Set: 64

Answer

6.5 s

Work Step by Step

We know that: $$ 0 = -16t^2 +20t+550$$ Note, we subtract 550 since we want to find when the object is 550 feet off of the ground. Next, we find: $$x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$ Where b is the coefficient of the term with a variable raised to the first power, a is the coefficient of the squared term, and c is the coefficient of the term without a variable in front of it. Plugging in the given values and solving, we get: 6.5 s
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.