Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.2 - Solving Quadratic Equations by the Quadratic Formula - Exercise Set - Page 493: 61

Answer

5.557 cm. 16.115 cm

Work Step by Step

We know that the base of the triangle is (2x+4), while the height is x. This gives: $$ A = .5bh$$ $$42 = .5(x)(2x+4)$$ $$ 0 = x^2+2x-42$$ We know that: $$x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$ We simplify: $$x= \frac{-2 \pm \sqrt{2^2-4(1)(-42)}}{2(1)}$$ We only consider the positive values: x=5.557 cm We plug this in to find the other value: 2(5.557)+4 = 16.115 cm
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