Answer
$5$
Work Step by Step
Substituting the given values of the variables, the expression $\sqrt{b^2-4ac}$ evaluates to
\begin{array}{l}\require{cancel}
\sqrt{(-1)^2-4(3)(-2)}
\\\\=
\sqrt{1+24}
\\\\=
\sqrt{25}
\\\\=
5
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 8 - Section 8.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 484: 95
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