Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 484: 94

Answer

$2\sqrt{7}$

Work Step by Step

Substituting the given values of the variables, the expression $\sqrt{b^2-4ac}$ evaluates to \begin{array}{l}\require{cancel} \sqrt{(6)^2-4(1)(2)} \\\\= \sqrt{36-8} \\\\= \sqrt{28} \\\\= \sqrt{4\cdot7} \\\\= \sqrt{(2)^2\cdot7} \\\\= 2\sqrt{7} .\end{array}
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