Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 484: 96

Answer

$\sqrt{13}$

Work Step by Step

Substituting the given values of the variables, the expression $\sqrt{b^2-4ac}$ evaluates to \begin{array}{l}\require{cancel} \sqrt{(-3)^2-4(1)(-1)} \\\\= \sqrt{9+4} \\\\= \sqrt{13} .\end{array}
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