Answer
$\frac{16b^{6}}{a^{6}}$
Work Step by Step
$(\frac{3a^{8}b^{2}}{12a^{5}b^{5}})^{-2}$
=$\frac{(12)^{2}(a^{-16})(b^{-4})}{(3)^{2}(a^{-10})(b^{-10})}$
=$\frac{144(b^{-4+10})}{9(a^{-10+16})}$
=$\frac{16(b^{6})}{(a^{6})}$
=$\frac{16b^{6}}{a^{6}}$