Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 533: 6a



Work Step by Step

$(a^{-2}bc^{3})^{-3}$ =$(a^{-2})^{-3}\times b^{-3} \times (c^{3})^{-3}$ =$(a^{6})\times b^{-3} \times (c^{-9})$ =$(a^{6})\times \frac{1}{b^{3}} \times \frac{1}{c^{9}}$ =$\frac{a^{6}}{b^{3}c^{9}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.