#### Answer

$\frac{a^{6}}{b^{3}c^{9}}$

#### Work Step by Step

$(a^{-2}bc^{3})^{-3}$
=$(a^{-2})^{-3}\times b^{-3} \times (c^{3})^{-3}$
=$(a^{6})\times b^{-3} \times (c^{-9})$
=$(a^{6})\times \frac{1}{b^{3}} \times \frac{1}{c^{9}}$
=$\frac{a^{6}}{b^{3}c^{9}}$