Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 533: 6b

Answer

$\frac{a^{8}}{b^{4}c^{6}}$

Work Step by Step

$(\frac{a^{-4}b^{2}}{c^{-3}})^{-2}$ =$\frac{(a^{-4})^{-2}(b^{2})^{-2}}{(c^{-3})^{-2}}$ =$\frac{(a^{8})(b^{-4})}{(c^{6})}$ =$\frac{a^{8}}{b^{4}c^{6}}$
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