## Intermediate Algebra (6th Edition)

$x^{\frac{3}{8}}$
Let the expression be $y . x^{\frac{1}{8}} = x^{\frac{4}{8}}$ $y= \frac{x^{\frac{4}{8}}}{x^{\frac{1}{8}}}$ Using quotient rule for exponents, $\frac{a^{m}}{a^{n}} = a^{m-n}$ $y= x^{\frac{4}{8}-\frac{1}{8}}$ $y = x^{\frac{3}{8}}$ Substituting $y$ in the given expression, we get $x^{\frac{3}{8}} . x^{\frac{1}{8}} = x^{\frac{4}{8}}$