Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 80


$\sqrt[3] (y^{2}z)$

Work Step by Step

$\sqrt[9] (y^{6}z^{3})=(y^{6}z^{3})^{\frac{1}{9}}=y^{\frac{6}{9}}z^\frac{3}{9}=y^{\frac{2}{3}}z^\frac{1}{3}=(y^{2}z)^{\frac{1}{3}}=\sqrt[3] (y^{2}z)$
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