## Intermediate Algebra (6th Edition)

$a^{\frac{1}{3}}$
$x . a^{\frac{2}{3}} = a^{\frac{3}{3}}$ To find $x$ $x = \frac{a^{\frac{3}{3}}}{a^{\frac{2}{3}}}$ Using $\frac{a^{m}}{a^{n}} = a^{m-n}$ $x = a^{\frac{3}{3}-\frac{2}{3}}$ $x = a^{\frac{3-2}{3}}$ $x = a^{\frac{1}{3}}$