Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 471: 4

Answer

$a=\dfrac{13}{14}$

Work Step by Step

Multiplying both sides by the $LCD= 8 ,$ the solution to the given equation, $ \dfrac{a-1}{2}+a=2-\dfrac{2a+7}{8} ,$ is \begin{array}{l}\require{cancel} 4(a-1)+8(a)=8(2)-1(2a+7) \\\\ 4a-4+8a=16-2a-7 \\\\ 4a+8a+2a=16-7+4 \\\\ 14a=13 \\\\ a=\dfrac{13}{14} .\end{array}
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