Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 471: 1d

Answer

$-a-7b+\dfrac{7}{12}$

Work Step by Step

Using the Distributive Property and then combining like terms, the given expression, $ \dfrac{1}{2}(4a-6b)-\dfrac{1}{3}(9a+12b-1)+\dfrac{1}{4} ,$ simplifies to \begin{array}{l}\require{cancel} 2a-3b-3a-4b+\dfrac{1}{3}+\dfrac{1}{4} \\\\= (2a-3a)+(-3b-4b)+\left(\dfrac{1}{3}+\dfrac{1}{4}\right) \\\\= (2a-3a)+(-3b-4b)+\left(\dfrac{4}{12}+\dfrac{3}{12}\right) \\\\= -a-7b+\dfrac{7}{12} .\end{array}
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