Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 471: 3

Answer

$x=\dfrac{21}{11}$

Work Step by Step

Multiplying both sides by the $LCD= 8 ,$ the solution to the given equation, $ \dfrac{x+5}{2}+\dfrac{1}{2}=2x-\dfrac{x-3}{8} ,$ is \begin{array}{l}\require{cancel} 4(x+5)+4(1)=8(2x)-1(x-3) \\\\ 4x+20+4=16x-x+3 \\\\ 4x-16x+x=3-20-4 \\\\ -11x=-21 \\\\ x=\dfrac{-21}{-11} \\\\ x=\dfrac{21}{11} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.