#### Answer

$24 \text{ cubic meters}$

#### Work Step by Step

The variation model described by the problem is $
V=kT
,$ where $V$ is the volume of a gas and $T$ is the temperature.
Substituting the given values in the variation model above results to
\begin{array}{l}\require{cancel}
20=k(300)
\\\\
\dfrac{20}{300}=k
\\\\
\dfrac{1}{15}=k
.\end{array}
Therefore, the variation equation is $
V=\dfrac{1}{15}T
.$
Using the variation equation above, then
\begin{array}{l}\require{cancel}
V=\dfrac{1}{15}(360)
\\\\
V=24
.\end{array}
Hence, the new volume is $
24 \text{ cubic meters}
.$