Intermediate Algebra (6th Edition)

$24 \text{ cubic meters}$
The variation model described by the problem is $V=kT ,$ where $V$ is the volume of a gas and $T$ is the temperature. Substituting the given values in the variation model above results to \begin{array}{l}\require{cancel} 20=k(300) \\\\ \dfrac{20}{300}=k \\\\ \dfrac{1}{15}=k .\end{array} Therefore, the variation equation is $V=\dfrac{1}{15}T .$ Using the variation equation above, then \begin{array}{l}\require{cancel} V=\dfrac{1}{15}(360) \\\\ V=24 .\end{array} Hence, the new volume is $24 \text{ cubic meters} .$