Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.7 - Variation and Problem Solving - Exercise Set - Page 397: 12

Answer

$24 \text{ cubic meters}$

Work Step by Step

The variation model described by the problem is $ V=kT ,$ where $V$ is the volume of a gas and $T$ is the temperature. Substituting the given values in the variation model above results to \begin{array}{l}\require{cancel} 20=k(300) \\\\ \dfrac{20}{300}=k \\\\ \dfrac{1}{15}=k .\end{array} Therefore, the variation equation is $ V=\dfrac{1}{15}T .$ Using the variation equation above, then \begin{array}{l}\require{cancel} V=\dfrac{1}{15}(360) \\\\ V=24 .\end{array} Hence, the new volume is $ 24 \text{ cubic meters} .$
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