Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.7 - Variation and Problem Solving - Exercise Set: 11

Answer

$187,239 \text{ tons}$

Work Step by Step

The variation model described by the problem is $ P=kN ,$ where $P$ is the amount of pollution and $N$ is the population. Substituting the given values in the variation model above results to \begin{array}{l}\require{cancel} 270000=k(460000) \\\\ \dfrac{270000}{460000}=k \\\\ k=\dfrac{27}{46} .\end{array} Therefore, the variation equation is $ P=\dfrac{27}{46}N .$ Using the variation equation above, then \begin{array}{l}\require{cancel} P=\dfrac{27}{46}(319000) \\\\ P=187239.13043478260869565217391304 .\end{array} Rounded to the nearest whole ton, the number of tons of pollution is $ 187,239 \text{ tons} .$
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