Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.3 - Simplifying Complex Fractions - Exercise Set - Page 361: 28

Answer

$\dfrac{5-2x}{x(1+2x)}$

Work Step by Step

The given expression, $ \dfrac{\dfrac{5}{x^2}-\dfrac{2}{x}}{\dfrac{1}{x}+2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\dfrac{5-2x}{x^2}}{\dfrac{1+2x}{x}} \\\\= \dfrac{5-2x}{x^2}\div\dfrac{1+2x}{x} \\\\= \dfrac{5-2x}{x^2}\cdot\dfrac{x}{1+2x} \\\\= \dfrac{5-2x}{\cancel{x}\cdot x}\cdot\dfrac{\cancel{x}}{1+2x} \\\\= \dfrac{5-2x}{x(1+2x)} .\end{array}
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