Answer
$\dfrac{2x+1}{y}$
Work Step by Step
The given expression, $
\dfrac{\dfrac{2}{x}+\dfrac{1}{x^2}}{\dfrac{y}{x^2}}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\dfrac{2x+1}{x^2}}{\dfrac{y}{x^2}}
\\\\=
\dfrac{\dfrac{2x+1}{\cancel{x^2}}}{\dfrac{y}{\cancel{x^2}}}
\\\\=
\dfrac{2x+1}{y}
.\end{array}
