Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.3 - Simplifying Complex Fractions - Exercise Set - Page 361: 39

Answer

$\dfrac{x}{x^2-1}$

Work Step by Step

The given expression, $ \dfrac{1}{x-x^{-1}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{1}{x-\dfrac{1}{x^1}} \\\\= \dfrac{1}{\dfrac{x^2-1}{x}} \\\\= \dfrac{x}{x^2-1} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.