Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 403: 7



Work Step by Step

Factoring the expressions and then cancelling the common factor/s between the numerator and the denominator, the given expression, $ \dfrac{x-12}{12-x} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{-1(-x+12)}{12-x} \\\\= \dfrac{-1(12-x)}{12-x} \\\\= \dfrac{-1(\cancel{12-x})}{\cancel{12-x}} \\\\= -1 .\end{array}
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