Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 403: 12b

Answer

$\$77$

Work Step by Step

Substituting $x$ with $ 100 $ in $C(x)=\dfrac{35x+4200}{x}$, then, \begin{array}{l}\require{cancel} C(100)=\dfrac{35(100)+4200}{100} \\\\ C(100)=\dfrac{7700}{100} \\\\ C(100)=77 .\end{array} Hence, the average cost is \$77.
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