Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review: 10

Answer

$\dfrac{1}{x-7}$

Work Step by Step

Factoring the expressions and then cancelling the common factor/s between the numerator and the denominator, the given expression, $ \dfrac{x+7}{x^2-49} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x+7}{(x+7)(x-7)} \\\\= \dfrac{\cancel{x+7}}{(\cancel{x+7})(x-7)} \\\\= \dfrac{1}{x-7} .\end{array}
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