Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 8



Work Step by Step

Using scientific notation and the laws of exponents, the given expression, $ \dfrac{(0.0024)(0.00012)}{0.00032} $, simplifies to \begin{array}{l} \dfrac{(2.4\times10^{-3})(1.2\times10^{-4})}{3.2\times10^{-4}} \\\\= (2.4)(1.2)\div3.2\times10^{-3+(-4)-(-4)} \\\\= 0.9\times10^{-3-4+4} \\\\= 0.9\times10^{-3} \\\\= 9.0\times10^{-4} .\end{array}
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