Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 4

Answer

$$\frac{-y^{40}}{z^5}$$

Work Step by Step

We have $$(\frac{-xy^{-5}z}{xy^3})^{-5}$$ Simplifying $$(\frac{-z}{y^5y^3})^{-5}$$ $$(\frac{-z}{y^8})^{-5}$$ $$(\frac{-y^8}{z})^{5}$$ $$\frac{-y^{40}}{z^5}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.