Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 332: 25

Answer

$$n=-\frac{8}{7}$$ $$n=4$$

Work Step by Step

We have $$3n(7n-20)=96$$ Expanding the expression and sending all the elements to the left side $$21n^2-60n-96 = 0$$ $$3(7n^2-20n-32)=0$$ Factorizing $$(n-4)(7n+8)=0$$ Solving each parenthesis 1)$$n-4=0$$ $$n=4$$ 2) $$7n+8=0$$ $$7n=-8$$ $$n=-\frac{8}{7}$$
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